We start to solve this by looking for the formula that let us calculate an average value, this formula would be:
![save=(1+s2+s3+s4+s5)/(5)](https://img.qammunity.org/2023/formulas/mathematics/college/poey0ys6qwayssc3jfbwk5h1vlwadz1sgy.png)
where Save is the average score and s is the score of each exam, Since we know the value of the score Save and 4 of the exams we can replace them in the formula, like this:
And we can solve for s5, which is the score that we need to find, like this:
![\begin{gathered} 74*5=(88+80+83+74+s5)/(5)*5 \\ 74*5=88+80+83+s5 \\ 74*5-88-80-83-74=88+80+83+74-88-80-83-74+s5 \\ 74*5-88-80-83-74=s5 \\ s5=74*5-88-80-83-74=55 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/fq1muiul9yju1qmr8crogfr6746ur0fwdu.png)
Then, Pedro must have a 55 score on the fifth test