We need to first identify the center of the circle.
We see that the coordinate point of the center of the circle is (-1, -2).
The equation of a circle is given with the equation
![(x-h)^2+(y-k)^2=r^2](https://img.qammunity.org/2023/formulas/mathematics/college/5s77z5lwu6jnvb5vkwanu2jvhq5sh1qkc3.png)
where h is x, k is y, and r is the radius of the circle.
Therefore, we can plug in the coordinates first to find the h and k of the equation.
![\begin{gathered} (x-(-1))^2+(y-(-2))^2=r^2 \\ (x+1)^2+(y+2)^2=r^2_{} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/yhka027kukgjxsbm6bd2cxrh08n0i33wll.png)
Then, we need to determine r.
The circle intersects points (-6, -2) and (4, -2). We can simply subtract the x-coordinates from each other to find the diameter of the circle.
![-6-4=-10](https://img.qammunity.org/2023/formulas/mathematics/high-school/czgev4yl9l770oi2qbw3itscgikv88brv2.png)
Finally, we know the radius is half of the diameter:
![(-10)/(2)=-5](https://img.qammunity.org/2023/formulas/mathematics/high-school/pdb8mhd2nydlpf3bbcgnsw760jt444707o.png)
We can plug in the radius into the equation.
![\begin{gathered} (x+1)^2+(y+2)^2=(-5)^2_{}_{} \\ (x+1)^2+(y+2)^2=25 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/iz32b9euhsd27i9nzir7s2n3n82hzqv206.png)
Therefore, our final equation is Choice D:
![(x+1)^2+(y+2)^2=25](https://img.qammunity.org/2023/formulas/mathematics/high-school/zua5mclj8sdi5089q6gwbbyogwk6k9irly.png)