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A horizontal force of 30 N just starts to move a 9kg object. Findthe value of coefficient of static friction and angle of friction.

1 Answer

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Use the static friction formula.


\begin{gathered} \mu_s=(F)/(mg)=\frac{30N}{9\operatorname{kg}\cdot9.8\cdot(m)/(s^2)} \\ \mu_s=0.34 \end{gathered}

Therefore, the coefficient of static friction is 0.34. The angle of friction would be 180 because it's opposite to the direction of the movemNo ent.

User Ruchi
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