Answer:
P(getting a 5)=
P(number larger than 2)=
P(numbers which are odd) =
Explanation:
When a standard die is rolled, we get sample space as {1,2,3,4,5,6}
So, let's use formula
P(E)=
For part A:
Event is getting a 5.
So, out of 6 samples , we get one 5 as outcome
So,
P(getting a 5)=
For part B:
The numbers larger than 2 are {3,4,5,6}
So, p(number larger than 2)=
P(number larger than 2)=
For part C:
The numbers which are odd are {1,3,5}
So, p(numbers which are odd)=
P(numbers which are odd) =