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Find the factors of (x-5)^2-4=0 A. (X-5)(X-5)=0B.(X-7)(X+8)C.(X-3)(X-7)D.(X-5)(X+5)

User Bramus
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1 Answer

6 votes

First, let's expand the expression and reduce like terms:


\begin{gathered} (x-5)^2-4=0 \\ \rightarrow x^2-10x+25-4=0 \\ \rightarrow x^2-10x+21=0 \end{gathered}

Now, let's factor the new expression completely:


(x-3)(x-7)=0

Thereby, the correct answer is option C

User Leonardo Henriques
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