Given,
The equation of lines are,
Line A y = 2x – 3
Line B 2y = x + 3
Line C 4y = 3x – 2
Line D 2y = 4x – 1
Line E 3y = 2x – 2
The standard equation of line is,

Here, m is the slope of the line and c is y - intercept.
Taking the line A as,

On comparing the line A with standard equation of line then the slope of the line is obtained m = 2.
Taking the line B as,

On comparing the line B with standard equation of line then the slope of the line is obtained m = 1/2.
Taking the line C as,

On comparing the line C with standard equation of line then the slope of the line is obtained m = 3/4.
Taking the line D as,

On comparing the line D with standard equation of line then the slope of the line is obtained m = 2.