Step-by-step explanation:
We are given this molecular equation:
HCIO₄ (aq) + NaOH (aq) -----> H₂O (l) + NaCIO₄ (aq) Molecular Equation
And we have to find the net ionic equation. Before that, we have to write the total ionic equation. We have to split all the compounds that we can into its ions. We have 3 aqueous solution:
HClO₄ (aq) ----> H⁺ (aq) + ClO₄⁻ (aq)
NaOH (aq) ----> Na⁺ (aq) + OH⁻ (aq)
NaCIO₄ (aq) ----> Na⁺ (aq) + ClO₄⁻ (aq)
And H₂O is a liquid so we leave it like that. The total ionic equation will be:
H⁺ (aq) + ClO₄⁻ (aq) + Na⁺ (aq) + OH⁻ (aq) ----> H₂O (l) + Na⁺ (aq) + ClO₄⁻ (aq) Total Ionic Equation
Finally to get the net ionic equation we have to cancel the spectator ions. By definition they are ions that doesn't participate in the reaction and are found on both sides of the equation.
Spectator ions = ClO₄⁻ (aq) and Na⁺ (aq)
H⁺ (aq) + OH⁻ (aq) ----> H₂O (l) Net Ionic Equation
Answer: The spectator ions are ClO₄⁻ (aq) and Na⁺ (aq).
The net ionic equation is: H⁺ (aq) + OH⁻ (aq) ----> H₂O (l)