Question

I need help with this question somebody please answer it it’ll take only a Genius

Answer 1

Answer:
`\begin{gathered} 7^(-2) \\ first\text{ blank = 7} \\ second\text{ blank \lparen exponent\rparen = -2} \end{gathered}`

Step-by-step explanation:

Given:

`(1)/(49)`

To find:

to write the number with a negative exponent

`\begin{gathered} 49\text{ is a perfect square} \\ 49\text{ = 7}^2 \\ \\ (1)/(49)\text{ = }(1)/(7^2) \end{gathered}`
`\begin{gathered} writing\text{ the expression in the form of a negative exponent:} \\ (1)/(a^b)\text{ = a}^(-b)\text{ \lparen one of the exponent rules\rparen} \\ \\ (1)/(7^2)\text{ = 7}^(-2) \end{gathered}`