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let d be the distance of a paper delivery truck in feet. Determine the average speed of the truck using the given formula and the specified time interval. a. d=t^2 from t=5 to t = 30b. d= 1/3(9t^2 + 155t - (11t - 6)) from t = 2 to t = 4.

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To find the average we need to add the value of the function for the given values of t and divide it by the elapsed t.

a. d=t² from t = 5 to t = 30.


\begin{gathered} d(5)=(5)^2=25_{} \\ d(30)=(30)^2=900_{} \end{gathered}
\begin{gathered} d_{\text{avg}}=(900-25)/(30-5)=(875)/(25) \\ d_{\text{avg}}=35 \end{gathered}

The average of the first function on that interval is 35.

User Jvhang
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