Answer and explanation
we are given the reaction equation between ammonia and oxygen to produce nitrogen gas and water.
firstly we balance the reaction as follows:
4NH₃(g) + 3O₂(g) → 2N₂(g) + 6H₂O(g)
now that we have a balanced chemical equation, we can see that 4 moles of ammonia react with 3 moles of oxygen in the balanced reaction.
therefore, 0.23 moles of ammonia will react with:
3/4 x 0.23 = 0.17 moles of oxygen
if we have 0.55 moles of oxygen reacting we can determine how many gram of water will be produced as follows;
from the balanced chemical reaction we see that we have 3 moles of oxygen reacting to form 6 moles of water.
therefore, the number of moles of water that will be produced from 0.55 moles of oxygen will be ;
6/3 x 0.55 = 1.1 moles of water will be formed.
now that we have the moles of oxygen, we can determine the mass of water produced using the following equation
mass = n x M
where n is moles
M is Molar mass of water
mass = 1.1 moles x 18.00 g/mol
= 19.8 grams of water will be produced
c. to determine the moles of nitrogen that will be produced when 12.6 grams of ammonia react can be determined by first calculating the number of moles of ammonia using the following equation
moles = mass (g) / Molar mass (g/mol)
moles = 12.6 g / 17.031 g/mol
= 0.74 moles of ammonia
we know from the balance reaction equation that 4 moles of ammonia produce 2 moles of nitrogen gas
therefore, the number of moles of nitrogen that will be formed will be
2/4 x 0.74
= 0.37 moles of nitrogen gas