Question

What is the solution to the equation below? (Round your answer to twodecimal places.)5.In x = 3.5

Answer 1

Given the equation:

`5\cdot\ln x=3.5`

Solve for x as follows:

`\begin{gathered} \ln x=(3.5)/(5) \\ \\ \ln x=0.7 \\ \\ x=e^(0.7)\approx2.014 \end{gathered}`

Rounding to two decimals

So, the answer will be x = 2.01