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A pack of dogs is pulling a 72.0 kg sled with a net force of - 450N If friction is ignored, what is the acceleration of the sled?

A pack of dogs is pulling a 72.0 kg sled with a net force of - 450N If friction is-example-1
User Boeboe
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1 Answer

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Given,

The mass of the sled, m=72.0 kg

The net force with which the sled is being pulled, F=-450 N

From Newton's second law, the force applied to an object is equal to the product of the mass of the object and the accleration of the object produced due to the applied force.

Thus, the force with which the sled is being pulled is given by,


F=ma

On substituting the known values,


\begin{gathered} -450=72.0* a \\ a=(-450)/(72.0) \\ =-6.3\text{ m/s}^2 \end{gathered}

Thus the acceleration of the sled is -6.3 m/s².

User Jorel
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