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Solve the equations (the answer might be no solution or all real numbers)4(A + 4) - 9(A - 4)= 3711=7 - (1- y)3+7(p - 10)= - 38 -(5 -3p)20 + 5(3-5A)= -5(A-6)+5

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Solution:

Consider the following equations:

Equation 1:


4\mleft(A+4\mright)-9\mleft(A-4\mright)=37

Equation 2:


11=7-1-y

Equation 3:


3+7\mleft(p-10\mright)=-38-\mleft(5-3p\mright)

Equation 4:


20+5\mleft(3-5A\mright)=-5\mleft(A-6\mright)+5

From equation 1, we get:


4A\text{ + 16-9A+36= 37}

this is equivalent to:


4A\text{ -9A = 37-16-36}

this is equivalent to:


-5A\text{ = -15}

solving for A, we get:


A\text{ = }(15)/(5)=\text{ 3}

then A = 3.

From equation 4, we get:


20\text{ + 15 -25A = -5A +30+5}

this is equivalent to:


-25A+5A\text{ = 30 +5 -20-15}

this is equivalent to:


-20A\text{ = }0

Thus A = 0.

But this is a contradiction since we had found that A =3. Then, the linear system has no solution (is incongruent).

User Harjatin
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