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What is the area of a sectorwhen 0 = 17/36 radians and r = 2?

What is the area of a sectorwhen 0 = 17/36 radians and r = 2?-example-1
User Spot
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1 Answer

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To answer this question we will use the following formula to compute the area of a sector of radius r and central angle Θ:


Area=(r^2\theta)/(2).

Substituting the given information we get:


Area=(2^2*(17\pi)/(36))/(2).

Simplifying the above result we get:


Area=(4*(17\pi)/(36))/(2)=(17\pi)/(18)

Answer:


(17\pi)/(18)sq\text{ units.}

User Serhii Kyslyi
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