Conditional probability:
![P(A|B)=(P(A\cap B))/(P(B))](https://img.qammunity.org/2023/formulas/mathematics/college/gyv83ae8bjeqduarjrt7upej9ph8thnwew.png)
The probability that A occurs given that B has occurred is given in the formula above.
As in our problem we are asked for the probability that a customer ordered a hot drink (event A) given that he or she ordered a large (event B), then we can work with the formula.
• The union between hot drink and large can be written as follows, and this is equal to 22 as we can see in the table.
![P(A\cap B)=P(Hot\cap Large)=22](https://img.qammunity.org/2023/formulas/mathematics/college/6y6lu6vz0rtzoitwegx3jnfnq91fzozz3b.png)
• The probability of a large (event B) is the addition of all the possibilities of ordering large:
![P(B)=P(Large)=22+5=27](https://img.qammunity.org/2023/formulas/mathematics/college/qm30p8p4abkv8t1nfo7k3acnz5tpi4ma89.png)
Finally, we replace these values in the formula:
![P(Hot|Large)=(P(Hot\cap Large))/(P(Large))](https://img.qammunity.org/2023/formulas/mathematics/college/1o19lzb8d14uawveuo5hl8ifj168s9i07i.png)
![P(Hot|Large)=(22)/(27)](https://img.qammunity.org/2023/formulas/mathematics/college/wg6ikxsir1qcjdfeu93ibo441o3onlcv94.png)
Answer:
![P(Hot|Large)\approx0.81](https://img.qammunity.org/2023/formulas/mathematics/college/qe0cgcpnfcoq038fh1krbzhanbn9stm7y5.png)