Given
mj = 65 kg
mc = 78 kg
voj = 5.75 m/s
after collision
vfj = vfc = 0 m/s
Procedure
The law of momentum conservation can be stated as follows. For a collision occurring between object 1 and object 2 in an isolated system, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.

The velocity before the collision would be 4.8m/s