Question

Need help with these two questions please

Answer 1

`3)\log_(49)7=\log_(7^2)7=(1)/(2) \log_7 7=(1)/(2) *1=(1)/(2) \\\\4)\log40=\log(10*4)=\log_(10)10+\log_(10)2^2=1+2\log_(10)2\\\log_(10)2<0.5 =>2\log_(10)2<1\\=>\log40\approx1.602`