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Object A is moving around another object B by thegravitational attraction. What is the acceleration of object A, ifthe distance between the two objects is 5.24 x 10^3 m, and themass of object B is 4.21 x 10^21 kg? Estimate G as 6.67 * 10^-11 N(m/kg)

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Take into account that the gravitational force between two object with masses mA and mB is given by the following formula:


F=(Gm_Am_B)/(r^2)

where,

G = 6.67*10^-11 Nm/kg

mA: mass of object A = ?

mB: mass of object B = 4.21*10^21 kg

r: distance between object A and B = 5.24*10^3 m

Moreover, consider that the force is also equal to the product of the mass by the acceleration, due to the Newton Secon Law, then, you have:


m_Aa=(Gm_Am_B)/(r^2)

Then, cancel out mA both sides and solve for the acceleration of object A and replace the values of the rest of the parameters, as follow:


a=(Gm_B)/(r^2)=\frac{(6.67\cdot10^(-11)N\frac{m^2}{\operatorname{kg}^2})(4.21\cdot10^(21)kg)}{(5.24\cdot10^3m)^2}=10226.93(m)/(s^2)

Hence, the acceleration of object A is approximately 10226.93 m/s^2

, as follow:

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