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Angle A is complementary to Angle B, Angle B is supplementary to Angle C, and the ratio of Angle A to Angle C is 11:26. Find the measurements of Angle B.

User Andronikus
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Since the complementary angles have a sum of 90 degrees

Since


A+B=90^(\circ)\rightarrow(1)

Since the supplementary angles have a sum of 180 degrees

Since


B+C=180^(\circ)\rightarrow(2)

Subtract (1) from (2) to eliminate B


\begin{gathered} (B-B)+(C-A)=(180-90) \\ C-A=90\rightarrow(3) \end{gathered}

Since the ratio between A and C is 11: 26

Then the difference in ratio between C and A is


\begin{gathered} C-A=26x-11x \\ C-A=15x\rightarrow(4) \end{gathered}

Equate (3) and (4) to find x


15x=90

Divide both sides by 15


\begin{gathered} (15x)/(15)=(90)/(15) \\ x=6 \end{gathered}

Substitute x in the ratio of A and C to find them


\begin{gathered} A=11x \\ A=11*6 \\ A=66^(\circ) \end{gathered}

Substitute it in equation (1) to find B


66+B=90

Subtract 66 from both sides


\begin{gathered} 66-66+B=90-66 \\ B=24^(\circ) \end{gathered}

Angle B is 24 degrees

User DrDee
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