SOLUTION
Let us make a graph for the table. For this graph, we will take the first year (1990) as 0 and each subsequent year by adding 2 to the previous ones
The graph is shown below.
We can see that it is a line graph that slopes downwards.
Hence, the graph is linear.
The model for the graph is given as
![\begin{gathered} y_1\sim ax_1+b \\ \text{where }a=-22.803,b=736.727 \\ y_{}=-22.803x_{}+736.727 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/swz0aodz2vphpo4hbd9kqwfi6yjl3twdiy.png)
Hence, the graph model is
![y_{}=-22.803x_{}+736.727](https://img.qammunity.org/2023/formulas/mathematics/college/t7g7h7gzvmy0jslm4x7rilts6txntwwu3b.png)
What year will number of unemployed reach 5?
We will use the graph model to determine this.
This becomes
![\begin{gathered} y_{}=-22.803x_{}+736.727 \\ So,\text{ here, y = 5. And we will find x} \\ 5_{}=-22.803x_{}+736.727 \\ 22.803x=736.727-5 \\ 22.803x=731.727 \\ x=(731.727)/(22.803) \\ x=32.089 \\ x\text{ is approximately 32} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/hpqiamuc6viovbyywl56vuug1or2uonhr0.png)
Now, since we took 1990 as 0, the year when the number of unemployed will be 5 becomes
![1990+32=2022](https://img.qammunity.org/2023/formulas/mathematics/college/nbjkvnadm857320fzj6dwt1jbnwdp80gmc.png)
Hence, the answer is year 2022