Question

Need help figuring out . suppose it passes through (0,-2) and (9.5,0)

Answer 1

Lets suppose tha the graph passes through points

`\begin{gathered} (x_1,y_1)=(0,-2) \\ \text{and} \\ (x_2,y_2)=(9.5,0) \end{gathered}`

Then, the slope of the dashed line is given by

`m=(y_2-y_1)/(x_2-x_1)=(0-(-2))/(9.5-0)`

which gives

`m=(y_2-y_1)/(x_2-x_1)=(2)/(9.5)=0.21052`

Then, we can write

`y=mx+b\Rightarrow y=0.21052x+b`

where the y-intercept can be founded by substituting the first point, that is,

`\begin{gathered} -2=0.21052(0)+b \\ b=-2 \end{gathered}`

Then, the dashed line has equation

`y=0.21052x-2`

Finally, since the values of the red region are above the dashed line then, the inequality which represents the red region is:

`y>0.21052x-2`