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Kepler's law is still confusing me even with all the info I've gathered, I attached an example question that I've been stuck on for a bit to work on.

Kepler's law is still confusing me even with all the info I've gathered, I attached-example-1
User Rralf
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1 Answer

5 votes

Given

Mass is


m=5.98*10^(24)kg

Distance is


d=1.92*10^8m

To find

The orbital period.

Step-by-step explanation

The orbital speed is given by


v=\sqrt[]{(Gm)/(d)}

where G is the gravitational constant

Putting the values,


\begin{gathered} v=\sqrt[]{6.67*10^(-11)*5.98*(10^(24))/(1.92*10^8)} \\ \Rightarrow v=1441.33\text{ m/s} \end{gathered}

The orbital period is


\begin{gathered} T=\frac{2\pi\text{ d}}{v} \\ \Rightarrow T=(2\pi*1.92*10^8)/(1441.33) \\ \Rightarrow T=836985s\text{ =9.7 days} \end{gathered}

Conclusion

The orbital period is 9.7 days

User Kurdtpage
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