Question

How do you solve this problem? Not used to one with a fraction

Answer 1

`(2)/(3)x-2\ge0`

Solve for x:

Multiply both sides by 3:

`\begin{gathered} 3((2)/(3)x-2)\ge0 \\ 2x-6\ge0 \end{gathered}`

Add 6 to both sides:

`\begin{gathered} 2x-6+6\ge0+6 \\ 2x\ge6 \end{gathered}`

Divide both sides by 2:

`\begin{gathered} (2x)/(2)\ge(6)/(2) \\ x\ge3 \end{gathered}`