Question

Find the x- and y-intercepts of the parabola y– x² + 4x – 4.Enter each intercept as an ordered pair (x, y). Use a comma to separate the ordered pairs of multipenter an exact answer or round to 2 decimal places. If there are no solutions or no real solutions fo

Answer 1

x-intercept = (2, 0), (2, 0)

y-intercept = (0, -4)

Step-by-step explanation

The intercept refers to the point(s) where curves cross the axis.

y = -x² + 4x - 4

when x = 0

y = -x² + 4x - 4

y = -(0²) + 4(0) - 4

y = 0 + 0 - 4

y = -4

y-intercept = (0, -4)

when y = 0

y = -x² + 4x - 4

0 = -x² + 4x - 4

x² - 4x + 4 = 0

x² - 2x - 2x + 4 = 0

x (x - 2) - 2 (x - 2) = 0

(x - 2) (x - 2) = 0

x = 2 twice

x-intercept = (2, 0), (2, 0)

Hope ths HelpS!!!