Question

An airplane is flying on a bearing of 170 degrees at 495 mph. Find the component form of the velocity of the airplane. Show and explain all work.

Answer 1

(-487.48, 85.96)

Step-by-step explanation:

The component form of the velocity can be found as

(vx, vy)

Where

vx = vcos(170)

vy = vsin(170)

So, replacing the velocity v by 495 mph, we get:

vx = (495)cos(170)

vx = -487.48

vy = 495sin(170)

vy = 85.96

Therefore, the answer is

(-487.48, 85.96)