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The table represents hourly fees, in dollars, charged for a random sample of grant writing consultants working in two states.Hourly Fees (dollars)40, 50, SO, 60, 60, 70, 70, 70, 75, 80,80, 90, 90, 90, 90, 100, 110, 130, 130, 150ArtzonaTexas30, 30, 50, 60, 60, 70, 70, 70, 75, 80,80, 90, 90, 90, 100, 120, 130, 130, 140, 140Based on the table, which statement is true?O A. The mean hourly fee is the same for consultants in both states.B. The median hourly fee is the same for consultants in both states.OC. The mean hourly fee charged by consultants in Arizona is greater than the mean hourly fee charged by consultants in Texas,O D. The median hourly fee charged by consultants in Arizona is greater than the median hourly fee charged by consultants in Texas.O E. The range of hourly fees charged by consultants in Arizona is greater than the range of hourly fees charged by consultants in Texas.

1 Answer

6 votes

ANSWER

B. The median hourly fee is the same for consultants in both states

Step-by-step explanation

This is a table showing the mean, median and range in both states:

The mean in Texas is greater than the mean in Arizona, so options A and C are incorrect.

The range is the same in both states, so option E is not correct neither.

The remaining options involve the median, which is the same in both states, so the correct option is B.

How to find the mean?


\bar{x}=(\sum ^n_(i=1)x_i)/(n)

In both data sets the number of data is n = 20.

How to find the median?

The median is the data which is right in the middle of all data - if the data is ordered from least to greatest. In this case, the number of data is even, so the median is the mean between the 10th value and the 11th value. In this case, in both states these values are both 80:


(80+80)/(2)=80

How to find the range?

The range is the difference between the greatest number of the data set and the least number.

For Arizona:


R=150-40=110

For Texas:


R=140-30=110

The table represents hourly fees, in dollars, charged for a random sample of grant-example-1
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