Answer:
29.3feet
Explanation:
In ΔUVW, the measure of ∠W=90°, the measure of ∠U=19°, and WU = 85 feet. Find the length of VW to the nearest tenth of a foot.
From the triangle given
<W = 90 degrees
<U = 19 degrees
<V = 180 - (90+19)
<V = 180 - 109
<V = 71 degrees
Using SOH CAH TOA
tan theta = opp/adj
tan <V = WU/VW
tan 71 = 85/VW
VW = 85/tan 71
VW = 85/2.9042
VW = 29.27
Hence the length of VW to the tenth of a foot is 29.3feet