To solve this problem we need to use the conditions to write an equation, so Q will be the number of quarters and D will be the number of dimes so the first condition is:
the sum of quartes (0.25) plus dimes (0.10) are $1.15
![Q(0.25)+D(0.10)=1.15](https://img.qammunity.org/2023/formulas/mathematics/college/s67c5eeflyvztavdcxvndudwd9frfz6qit.png)
the second condition is; she has one more dimes than quarters so:
![Q+1=D](https://img.qammunity.org/2023/formulas/mathematics/college/qkea1dkbf9mczgltv9102igbuv9my4615e.png)
So we can replace the secon equation into the first equation so:
![Q(0.25)+(Q+1)(0.10)=1.15](https://img.qammunity.org/2023/formulas/mathematics/college/mp51oh33h1k5dkcyv4wbs0rqdvbpg33svs.png)
Now we can simplify the equation so:
![0.25Q+0.10Q+0.10=1.15](https://img.qammunity.org/2023/formulas/mathematics/college/vdmlw1bzk86lmcr1i9o3k30nf38zya38wt.png)
And finally we solve for Q so:
![\begin{gathered} 0.35Q=1.15-0.10 \\ 0.35Q=1.05 \\ Q=(1.05)/(0.35) \\ Q=3 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/n23nhyscnykea5ukwxptpv6hdflz31u5rb.png)
Now we can replace the value of Q in the second equation so:
![\begin{gathered} D=Q+1 \\ D=3+1 \\ D=4 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/qorjp1khiszxzz10iywe654scjlrs0g05t.png)
So Francesca have 3 quarters and 4 dimes