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Question 3 (1 point) A line passes through the points (0, - 4) and (2, - 11). If (x, y) is an arbitrary point on the line other than (0, - 4), which equation can you write for the line based on the fact that the slope of a line is constant? оа Y-0 x- (-4) 7 2 Ob y- (-4) x-0 7 2 Ос y-10 2 Il x- (-4) Od y-(-4). 2 7 X-0

Question 3 (1 point) A line passes through the points (0, - 4) and (2, - 11). If (x-example-1

1 Answer

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Step-by-step explanation:

we apply the slope formula:


m\text{ = }(y_2-y_1)/(x_2-x_1)

The points: (0, - 4) and (2, - 11)


\begin{gathered} x_1=0,y_1=-4,x_2=2,y_2\text{ = }-11 \\ m\text{ = }(-11-(-4))/(2-0) \\ m\text{ = }(-11+4)/(2) \\ m=(-7)/(2) \end{gathered}

The equation of the line becomes:


undefined

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