Question

Aloha, I also need C) C) What is the class width?

Answer 1

Given: The histogram below:

Required: To determine the following:

• The number of parks in the most frequent class.

,

• The total number of parks.

,

• The class width.

This is explained thus:

Question A: How many parks are in the most frequent class?

From the image, we can deduce that the most frequent class is "120 to 269" because it has the highest block. The number of parks in the class is:

`9`

Question B: What is the total number of parks?

From the image, we can deduce the following:

`\begin{gathered} Class\text{ }120\text{ }to\text{ }269\Rightarrow9parks \\ Class\text{ }270\text{ }to\text{ }419\Rightarrow7parks \\ Class\text{ }420\text{ }to\text{ }569\Rightarrow6parks \\ Class\text{ }570\text{ }to\text{ }719\Rightarrow3parks \\ Class\text{ }720\text{ }to\text{ }869\Rightarrow6parks \\ \\ Hence,the\text{ }total\text{ }number\text{ }of\text{ }parks=9+7+6+3+6=31parks \end{gathered}`

Question C: What is the class width?

From the image, we can deduce the following:

`\begin{gathered} Class\text{ }Intervals \\ 120-269 \\ 270-419 \\ 420-569 \\ 570-719 \\ 720-869 \end{gathered}`

We can determine the class boundary by subtracting 0.5 from the lower limit and adding 0,5 to the upper limit. Therefore, we have:

`\begin{gathered} Class\text{ }Boundaries \\ 119.5-269.5 \\ 269.5-419.5 \\ 419.5-569.5 \\ 569.5-719.5 \\ 719.5-869.5 \end{gathered}`

The class width is the difference between the upper-class boundary and the lower-class boundary. Therefore, we have:

`\begin{gathered} Class\text{ }Width=(269.5)-(119.5) \\ Class\text{ }Width=150 \end{gathered}`

Hence, the answers review is:

`\begin{gathered} (a)\text{ }9\text{ }parks \\ \\ (b)\text{ }31\text{ }parks \\ \\ (c)\text{ }Class\text{ }width=150 \end{gathered}`