Question

How much heat is required to raise the temperature of 67.0 g of water from its melting point to its boiling point?Update: Result in KJ

Answer 1

Q=28.032 KJ

Procedure

To solve this problem, we will consider that we are speaking of liquid water, and we want to calculate the heat to take water from 0 °C to 100 °C without passing from ice to liquid or liquid to gas. Additionally, we are at 1 atm, so the water boils at 100 °C.

Based on the previous, we have the formula

`Q=mc\Delta T`

Where,

Q=heat energy

m=mass

c=specific heat capacity

Δ T=change in temperature

Specific heat of water 4184 J/kg°C

Substituting the values

`Q=0.067\text{ kg }4184\frac{\text{J}}{\text{ Kg}\degree\text{C}}(100-0)\degree C=28032.8\text{ J}`

By transforming the previous result into kilojoules by dividing by 1000, we have

Q=28.032 KJ