Step-by-step explanation:
We need to discover the limiting and excess reactant first.
For this, we use the reaction equation ratio between CaC2 + 2H2O.
The equation:
CaC2 + 2H2O --> Ca(OH)2 + C2H2
tells us that 1 mole of CaC2 react with 2 mol of H2O.
The question gives us 8 moles of CaC2 and 3 moles of H2O.
we can see that CaC2 is in excess and H2O is the limiting reactant.
So:
1 mole of CaC2 --- 2 mol of H2O
x mole of CaC2 --- 3 moles of H2O
x = 1.5 moles of CaC2.
1 mole of CaC2 produces 1 mole of C2H2.
So 1.5 moles of CaC2 produces 1.5 moles of C2H2.
Answer: 1.5 moles of C2H2.