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A coin is tossed 3 times. Find the sample space of the experiment, what is the probability of "at least two heads", name a different event with the same probability as " at least two heads."

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Given:

A coin is tossed 3 times.

To find the probability of getting at least two heads:

First, we write the sample space.


\begin{gathered} S=\mleft\lbrace\text{HHH, HHT, HTH, THH, HTT, TTH, THT, TTT}\mright\rbrace \\ n(S)=8 \end{gathered}

A be the event of getting at least two heads.


\begin{gathered} A=\mleft\lbrace\text{HHH, HHT, HTH, THH}\mright\rbrace \\ n(A)=4 \end{gathered}

So, the probability of getting at least two heads is


\begin{gathered} P(A)=(n(A))/(n(S)) \\ =(4)/(8) \\ =(1)/(2) \end{gathered}

Hence, the probability is,


(1)/(2)

The event of getting at least two tails is also getting the same probability as at least two heads.

User Cameron Hurd
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