Question

Write an exponential function whose graph passes through
the points (0, -3) and (4, -48)

Answer 1

`y = -3(2^(x))`

Explanation:

y =
`kb^(x)`

Use (0, -3) to find k

`-3 = kb^(0) = k(1) = k\\`

So, k = -3

Now use (4, -48) to find b

-48 =
`-3b^(4)`

`b^(4)` = 16

b = 2

Since k = -3 and b = 2,
`y = -3(2^(x))`