We have the next equation

First we need o make the equation equal to zero

we have a quadratic equation,we will have 2 solutions, so we will use the general formula to find the solutions to this equation
![x_(1,2)=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}](https://img.qammunity.org/2023/formulas/mathematics/college/li72dimqx1poek8bdg3bs589861h83kfxl.png)
in our case
a=2
b=11
c=15
![x_(1,2)=\frac{-11\pm\sqrt[]{11^2-4(15)(2)}}{2(2)}_{}](https://img.qammunity.org/2023/formulas/mathematics/high-school/i102oqz1t4zoyddldlgb23qi7diknh2bhg.png)
![x_(1,2)=\frac{-11\pm\sqrt[]{121-120}}{4}=(-11\pm1)/(4)](https://img.qammunity.org/2023/formulas/mathematics/high-school/t9sgrczv9uzhtgsi1ajdti93gac1p4d3ze.png)
for the first solution

for the second solution

the solutions to the equation given is

the correct choices are B. and C.