Question

Solve for the missing side lengths60°411А. Ои2/3, v = 2B.u√3, v = 4Cu = 2/3, v = 4D.O. 4, v = 3

Answer 1

In order to find u and v, we apply trigonometric ratios

`\begin{gathered} \sin 60^0=\frac{\text{ opposite}}{\text{hypotenuse}}=(u)/(4) \\ \frac{\sqrt[]{3}}{2}=(u)/(4) \\ u=2\sqrt[]{3} \end{gathered}`
`\begin{gathered} \cos 60^0=(v)/(4) \\ v=4*(1)/(2)\text{ = 2} \end{gathered}`

Therefore, u = 2√3, v = 2.

The right option is A.