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Which of the following values of x will make the equation 3(x-2) –- = 23 true? "Hint, plug in!X=1X=4X=5X=0

User Shaddix
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1 Answer

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\begin{gathered} 3(x-2)^2-4=23 \\ 3(x-2)^2-4+4=23+4 \\ 3(x-2)^2+(-4+4)=23+4 \\ 3(x-2)^2+0=27 \\ 3\mleft(x-2\mright)^2=27 \\ (x-2)^2=(27)/(3) \\ (x-2)^2=9 \\ √((x-2)^2)=√(9) \\ x-2=3 \\ x=3+2 \\ x=5 \\ \text{The value of x is 5. This value makes the equation true} \end{gathered}

User RSabet
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