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I need help answering this questiona) f(-5)b) f(-1)c) f(2)d) f(5)e) f(9)

I need help answering this questiona) f(-5)b) f(-1)c) f(2)d) f(5)e) f(9)-example-1
User AChampion
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1 Answer

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a) f(-5) = 27

b) f(-1) = 7

c) f(2) = 4

d) f(5) = 10

e) f(9) = 48

Step-by-step explanation:

a) To get f(-5), we will check the intervals in the piece-wise function.

-5 is less than 0

The interval where -5 belongs is x ≤0

We will substitute x for -5 in the function with interval x ≤ 0


\begin{gathered} f(x)\text{ = 2 - 5x} \\ f(-5_{})\text{ = 2 - 5(-5)} \\ f(-5)\text{ = 2 + 25} \\ f(-5)\text{ = 27} \end{gathered}

b) f(-1): To get f(-1), we will check the interval which has x = -1

The interval where -1 belongs is x ≤0


\begin{gathered} \text{function for }x\le0\text{ is f(x) = 2 - 5x} \\ f(-1)\text{ = 2 - 5(-1)} \\ f(-1)\text{ = 2 + 5 = 7} \end{gathered}

c) f(2): To get f(2), we will check the interval which has x = 2

The interval where 2 belongs is 0 < x < 9


\begin{gathered} \text{function for }0d) f(5): we will check the interval which has x = 5<p>The interval where 5 belongs to is 0 < x < 9</p>[tex]\begin{gathered} \text{function for }0e) f(9): 0 < x < 9 include numbers between 0 and 9 without including 0 and 9<p>the interval 9 will fall on is x ≥ 9</p>[tex]\begin{gathered} \text{function for x }\ge\text{ 9 is f(x) = }5x\text{ + 3} \\ f(9)\text{ = 5(9) + 3} \\ f(9)\text{ = 45 + 3} \\ f(9)\text{ = 48} \end{gathered}

User Gillis Haasnoot
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