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Through: ( 2,-3), slope = -3

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To find the equation of a line that passes through the point (2, -3) with a slope m = -3.

1. We need to use the Point-Slope Form of the line. Then, we have:


y-y_1=m(x-x_(1))\Rightarrow y-(-3)=-3\cdot(x-2)

In this equation, we have that:

x1 = 2, and y1 = -3

Then, solving the equation, we have:


y+3=-3x+6\Rightarrow y=-3x+6-3\Rightarrow y=-3x+3_{}

Therefore, the equation of the line in the Slope-Intercept Form is:


y=-3x+3

User Himel Nag Rana
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