Question

Evaluate the following
`b {}^(2) c {}^( - 1)`For b=8 and C=-4

Answer 1

We want to evaluate

`b^2c^(-1)`

for b = 8 and c = -4

Solution

From

`\begin{gathered} b^2c^(-1)=b^2*(1)/(c) \\ b^2c^(-1)=(b^2)/(c) \end{gathered}`

Put b = 8 and c = -4

`\begin{gathered} b^2c^(-1)=(b^2)/(c) \\ b^2c^(-1)=(8^2)/(-4) \\ b^2c^(-1)=(64)/(-4) \\ b^2c^(-1)=-16 \end{gathered}`

Therefore,

`b^2c^(-1)=-16`