The triangle given
The value of x and y can be obtained using trigonometric ratio
To get the correct solution:
To get x

![x=(3)/(\sin 60)=\frac{3}{\frac{\sqrt[]{3}}{2}}=\frac{6}{\sqrt[]{3}}=2\sqrt[]{3}](https://img.qammunity.org/2023/formulas/mathematics/college/hs4tj6e4a7mmk77j7k2p8fr7eksinqnc0t.png)
To get y
![\begin{gathered} \tan 60=(3)/(y) \\ y=(3)/(\tan 60) \\ y=\frac{3}{\sqrt[]{3}} \\ y=\sqrt[]{3} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/nkd15xyxp6dkt4vyex5jzpgz121x6ipdqm.png)
The next step is to compare the values of x and y Laz obtained with the correct answer.
Mistake: We can see that Laz did not use the correct trigonometric ratio to solve for x and y.