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If the length of a rectangle is increased by 20% and the width of the same rectangle is decreased by 20%, what is the effect on the area of the rectangle?

User Jiang YD
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The area of a rectangle is the product of its dimensions, that is:

Area = length * width

Then, if we call A the area, L the length, and W the width, the original area can be written as:

A = L * W

and the new area A' (after the increase of the length and the decrease of the width) would be:

A' = (1.2L) * (0.8W)

Notice that we wrote the 20% increase as 1.2 times the original length. That's so because, when L increases 20%, it becomes:

L' = L + 20% L

= (1 + 20%) L

= (1 + 0.2)L

= 1.2L

And, when W decreases 20%, it becomes:

W' = W - 20% W

= (1 - 20%) W

= (1 - 0.2) W

= 0.8 W

Now, proceeding to find the effect on the area, we find:

A' = (1.2L) * (0.8W)

= (1.2 * 0.8) * L * W

= 0.96 * (L * W)

= 0.96 * A

= (1 - 0.04) * A

= (1 - 4%) * A

= A - 4% A

Therefore, the effect on the area of the rectangle is the following:

• the ,area ,is ,decreased by 4%,.

User WillDonohoe
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