If we add x liters of the pure acid, we must have 90-x liters of 10% acid solution.
The equation that represents the situation:
![\begin{gathered} x+0.1(90-x)=.40(90) \\ x+9-0.1x=36 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/kpqu4c6sq1u41pbowfa1r58srzdv5lfcy6.png)
Solve for x to determine the liters of pure acid:
![\begin{gathered} 0.9x=36-9 \\ 0.9x=27 \\ x=(27)/(0.9) \\ x=30 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/n7oymmraje6mekkao4la94837uc2x160mf.png)
30 liters of pure acid need to be used to make the solution.
Then, 90-x would be the amount of the 10% acid solution:
![90-30=60](https://img.qammunity.org/2023/formulas/mathematics/college/r298avvw1nysv7t38i3gyglftkgpvz0und.png)
60 Liters of 10% acid solution is needed to make the solution.