What is the equation of the line that passes through the point (-8,-7)(−8,−7) and has a slope of 11?

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asked Oct 26, 2023 30.9k views

1 Answer

Pavel Agarkov · Answer 1 · 2023-11-01T04:27:25+0000

The equation of a line that passes through a given point having a coordinate (x₁, y₁) is given as

$\begin{gathered} y-y_1=m(x-x_1)\text{ ----- equation 1} \\ \text{where} \\ m\text{ is the slope of the line} \\ x_1,y_1\text{ is the coordinate of the point} \end{gathered}$

Given that the line has a slope of 1, and passes through a point of coordinate

(-8, -7), substitute these values into equation 1.

Thus,

$\begin{gathered} m\text{ = 1} \\ (x_(1,)y_1)\text{ =(-8, -7)} \\ y-(-7)\text{ = 1(x-(-8))} \\ y+7=1(x+8) \\ \text{open brackets} \\ y+7=x+8 \\ \Rightarrow y=x+1 \end{gathered}$

Hence, the equation of the line is

What is the equation of the line that passes through the point (-8,-7)(−8,−7) and has a slope of 11?

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