Question

Which of the following is equivalent to the complex number i^-9

Answer 1

the solution is

`-i`

because we know

`i^(-2)=-1`

and

`i^(-1)=-i`

so

`\begin{gathered} i^(-2)* i^(-2)* i^(-2)* i^(-2)* i^(-1)=i^(-9) \\ -1*-1*-1*-1* \end{gathered}`