Answer:
32 feet
Explanation:
given the following;
Length of wire = 40feet = hypotenuse
Base of the pole = 24 feet = adjacent
Required
Height of the pole (opposite)
Using the pythagoras theorem;
hyp^2 = opp^2 + adj^2
40^2 = 24^2 + opp^2
1600 = 576 +opp^2
opp^2 = 1600 - 576
opp^2 = 1024
opp = √1024
opp = 32feet
Hence the utility pole is 32feet tall