22.0k views
2 votes
HELP PLEASE SHOW STEPS I HAVE NO IDEA WHAT TO DO. I HAVE BEEN TRYING TO FIGURE IT OUT BUT I CAN’T.

HELP PLEASE SHOW STEPS I HAVE NO IDEA WHAT TO DO. I HAVE BEEN TRYING TO FIGURE IT-example-1

2 Answers

5 votes


\text{Area of rectangle}=\text{lengh}*\text{width}\\\text{Area of square}=\text{side}^2

You just need to find differens between rectangle and square


\text{lengh}*\text{width}-\text{side}^2\\\\(x+10)(2x+5)-(x+1)^2=2x^2+5x+20x+50-x^2-2x-1=x^2+23x+49


x^2+23x+49\:\text{is our answer}

User Brian Lam
by
7.6k points
9 votes

Answer:
x^(2) +23x+49

Explanation:

To find the area of the shaded region, you must find the area of the larger rectangle [(x+10)×(2x+5)] and subtract the area of the smaller rectangle [(x+1)×(x+1)] from it.

First, you simplify the larger rectangle's area:

(x+10)×(2x+5) =
2x^(2) +25x+50

Then, simplify the smaller rectangle's area:

(x+1)×(x+1) =
x^(2) +2x+1

Finally, subtract the smaller rectangle's area from the larger rectangle's area:


(2x^(2) +25x+50) - (x^(2) +2x+1) = x^(2) +23x+49

Therefore, the final answer is
x^(2) +23x+49.

I hope this helps!

User Barakisbrown
by
8.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories