Step-by-step explanation
We are given the distance Carmen jogged for three days:
On Monday, she jogged

On Tuesday, she jogged

On Thursday, she jogged

Thus, the total distance jogged for the three days will be the sum of all the distance jogged for the three days.

To simplify, we will have to get the lowest common multiple (l.c.m) of the denominator

The next step will be to express each term so they can have the same denominator
Thus, we will have

=>

Therefore, for the three days, she jogged a total of 14 miles