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Gelmir · Answer 1 · 2023-03-14T19:56:45+0000

The balanced equation for decane combustion is:

$2C_(10)H_(22(l))+31O_(2(g))\to20CO_(2(g))+22H_2O_((g))$

That is the balanced equation.

To calculate the volume of carbon dioxide, use the mass of decane and convert it to moles (use the molecular weight of decane, 142g/mol), then use the ration of the coefficients of carbon dioxide to decane to find the number of moles of CO2 produced:

$0.400\operatorname{kg}\cdot\frac{1000g}{\operatorname{kg}}\cdot(1mol)/(142g)=2.82mol$

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