The given equation is

This equation is exponential because the independent variable x is an exponent. In other words, the equation is not linear.
Now, to express the equation in standard form, we have to isolate y.
First, we sum 1 on each side.

Then, we divide the equation by 3.

We have to separate the fraction.
The standard form is

Where a = 1/3, b = 2, and c = 1/3.